Longest 480p AI video under $4.50 per clip, by Sume model
With a $4.50 ceiling per clip, Wan 3.0 runs 30 s at 480p; MiniMax H3 Max reaches 15 s. Full table of Sume models.

At a $4.50 ceiling per clip and 480p, the longest clip on Sume is 30 seconds on Wan 3.0 ($1.875). The shortest reach in the table is 15 seconds on MiniMax H3 Max. Every number is computed from the estimators that bill Sume jobs, using the Video Router duration limits.
Limits come from the Video Router docs and prices from API pricing, both read 2026-10-10.
Which model runs longest at 480p for $4.50?
Longest first. A model missing from the table has no clip at this tier that fits the ceiling, or does not offer the tier.
| Model | Resolution | Longest clip | Price of that clip |
|---|---|---|---|
| Wan 3.0 | 480p | 30 s | $1.875 |
| Seedance 2.5 | 480p | 16 s | $4.2988 |
| Seedance 2.0 | 480p | 15 s | $2.6366 |
| Seedance 2 Fast | 480p | 15 s | $2.1092 |
| MiniMax H3 | 480p | 15 s | $0.9375 |
| MiniMax H3 Max | 480p | 15 s | $0.9375 |
How do I set the length?
Send duration in whole seconds with the model id; the request fails if it is outside the model's range.
import os
import time
import requests
H = {"Authorization": f"Bearer {os.environ['SUME_API_KEY']}"}
job = requests.post(
"https://api.sume.com/v1/videos",
headers=H,
json={
"model": "wan-3.0",
"prompt": "A paper boat drifts down a rain-soaked street at dusk",
"duration": 30,
"resolution": "480p",
"aspect_ratio": "16:9",
},
).json()
while True:
s = requests.get(job["polling_url"], headers=H).json()
if s["status"] in ("completed", "failed"):
break
time.sleep(10)
print(s["status"], s.get("unsigned_urls"))What this leaves out
A ceiling is arithmetic, not a quality bar.
- Longer clips are not better clips; check the result before scaling a batch.
- Seedance prices assume 16:9; other ratios change the token count.
- Prices can change; re-read the pricing page before budgeting.
Sources
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Written by Sume